Optimal. Leaf size=625 \[ \frac{2 \sqrt{d+e x} (e f-d g)}{\sqrt{f+g x} \left (a g^2+c f^2\right )}-\frac{2 \sqrt{e} (e f-d g) \tanh ^{-1}\left (\frac{\sqrt{g} \sqrt{d+e x}}{\sqrt{e} \sqrt{f+g x}}\right )}{\sqrt{g} \left (a g^2+c f^2\right )}-\frac{\sqrt{e} \left (-\sqrt{-a} \sqrt{c} (e f-d g)+a e g+c d f\right ) \tanh ^{-1}\left (\frac{\sqrt{g} \sqrt{d+e x}}{\sqrt{e} \sqrt{f+g x}}\right )}{\sqrt{-a} \sqrt{c} \sqrt{g} \left (a g^2+c f^2\right )}+\frac{\sqrt{e} \left (\sqrt{-a} \sqrt{c} (e f-d g)+a e g+c d f\right ) \tanh ^{-1}\left (\frac{\sqrt{g} \sqrt{d+e x}}{\sqrt{e} \sqrt{f+g x}}\right )}{\sqrt{-a} \sqrt{c} \sqrt{g} \left (a g^2+c f^2\right )}+\frac{\sqrt{\sqrt{c} d-\sqrt{-a} e} \left (-\sqrt{-a} \sqrt{c} (e f-d g)+a e g+c d f\right ) \tanh ^{-1}\left (\frac{\sqrt{d+e x} \sqrt{\sqrt{c} f-\sqrt{-a} g}}{\sqrt{f+g x} \sqrt{\sqrt{c} d-\sqrt{-a} e}}\right )}{\sqrt{-a} \sqrt{c} \sqrt{\sqrt{c} f-\sqrt{-a} g} \left (a g^2+c f^2\right )}-\frac{\sqrt{\sqrt{-a} e+\sqrt{c} d} \left (\sqrt{-a} \sqrt{c} (e f-d g)+a e g+c d f\right ) \tanh ^{-1}\left (\frac{\sqrt{d+e x} \sqrt{\sqrt{-a} g+\sqrt{c} f}}{\sqrt{f+g x} \sqrt{\sqrt{-a} e+\sqrt{c} d}}\right )}{\sqrt{-a} \sqrt{c} \sqrt{\sqrt{-a} g+\sqrt{c} f} \left (a g^2+c f^2\right )} \]
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Rubi [A] time = 2.53051, antiderivative size = 625, normalized size of antiderivative = 1., number of steps used = 19, number of rules used = 9, integrand size = 28, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.321, Rules used = {908, 47, 63, 217, 206, 6725, 105, 93, 208} \[ \frac{2 \sqrt{d+e x} (e f-d g)}{\sqrt{f+g x} \left (a g^2+c f^2\right )}-\frac{2 \sqrt{e} (e f-d g) \tanh ^{-1}\left (\frac{\sqrt{g} \sqrt{d+e x}}{\sqrt{e} \sqrt{f+g x}}\right )}{\sqrt{g} \left (a g^2+c f^2\right )}-\frac{\sqrt{e} \left (-\sqrt{-a} \sqrt{c} (e f-d g)+a e g+c d f\right ) \tanh ^{-1}\left (\frac{\sqrt{g} \sqrt{d+e x}}{\sqrt{e} \sqrt{f+g x}}\right )}{\sqrt{-a} \sqrt{c} \sqrt{g} \left (a g^2+c f^2\right )}+\frac{\sqrt{e} \left (\sqrt{-a} \sqrt{c} (e f-d g)+a e g+c d f\right ) \tanh ^{-1}\left (\frac{\sqrt{g} \sqrt{d+e x}}{\sqrt{e} \sqrt{f+g x}}\right )}{\sqrt{-a} \sqrt{c} \sqrt{g} \left (a g^2+c f^2\right )}+\frac{\sqrt{\sqrt{c} d-\sqrt{-a} e} \left (-\sqrt{-a} \sqrt{c} (e f-d g)+a e g+c d f\right ) \tanh ^{-1}\left (\frac{\sqrt{d+e x} \sqrt{\sqrt{c} f-\sqrt{-a} g}}{\sqrt{f+g x} \sqrt{\sqrt{c} d-\sqrt{-a} e}}\right )}{\sqrt{-a} \sqrt{c} \sqrt{\sqrt{c} f-\sqrt{-a} g} \left (a g^2+c f^2\right )}-\frac{\sqrt{\sqrt{-a} e+\sqrt{c} d} \left (\sqrt{-a} \sqrt{c} (e f-d g)+a e g+c d f\right ) \tanh ^{-1}\left (\frac{\sqrt{d+e x} \sqrt{\sqrt{-a} g+\sqrt{c} f}}{\sqrt{f+g x} \sqrt{\sqrt{-a} e+\sqrt{c} d}}\right )}{\sqrt{-a} \sqrt{c} \sqrt{\sqrt{-a} g+\sqrt{c} f} \left (a g^2+c f^2\right )} \]
Antiderivative was successfully verified.
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Rule 908
Rule 47
Rule 63
Rule 217
Rule 206
Rule 6725
Rule 105
Rule 93
Rule 208
Rubi steps
\begin{align*} \int \frac{(d+e x)^{3/2}}{(f+g x)^{3/2} \left (a+c x^2\right )} \, dx &=\frac{\int \frac{\sqrt{d+e x} (c d f+a e g+c (e f-d g) x)}{\sqrt{f+g x} \left (a+c x^2\right )} \, dx}{c f^2+a g^2}-\frac{(g (e f-d g)) \int \frac{\sqrt{d+e x}}{(f+g x)^{3/2}} \, dx}{c f^2+a g^2}\\ &=\frac{2 (e f-d g) \sqrt{d+e x}}{\left (c f^2+a g^2\right ) \sqrt{f+g x}}+\frac{\int \left (\frac{\left (-a \sqrt{c} (e f-d g)+\sqrt{-a} (c d f+a e g)\right ) \sqrt{d+e x}}{2 a \left (\sqrt{-a}-\sqrt{c} x\right ) \sqrt{f+g x}}+\frac{\left (a \sqrt{c} (e f-d g)+\sqrt{-a} (c d f+a e g)\right ) \sqrt{d+e x}}{2 a \left (\sqrt{-a}+\sqrt{c} x\right ) \sqrt{f+g x}}\right ) \, dx}{c f^2+a g^2}-\frac{(e (e f-d g)) \int \frac{1}{\sqrt{d+e x} \sqrt{f+g x}} \, dx}{c f^2+a g^2}\\ &=\frac{2 (e f-d g) \sqrt{d+e x}}{\left (c f^2+a g^2\right ) \sqrt{f+g x}}-\frac{(2 (e f-d g)) \operatorname{Subst}\left (\int \frac{1}{\sqrt{f-\frac{d g}{e}+\frac{g x^2}{e}}} \, dx,x,\sqrt{d+e x}\right )}{c f^2+a g^2}-\frac{\left (c d f+a e g-\sqrt{-a} \sqrt{c} (e f-d g)\right ) \int \frac{\sqrt{d+e x}}{\left (\sqrt{-a}+\sqrt{c} x\right ) \sqrt{f+g x}} \, dx}{2 \sqrt{-a} \left (c f^2+a g^2\right )}-\frac{\left (c d f+a e g+\sqrt{-a} \sqrt{c} (e f-d g)\right ) \int \frac{\sqrt{d+e x}}{\left (\sqrt{-a}-\sqrt{c} x\right ) \sqrt{f+g x}} \, dx}{2 \sqrt{-a} \left (c f^2+a g^2\right )}\\ &=\frac{2 (e f-d g) \sqrt{d+e x}}{\left (c f^2+a g^2\right ) \sqrt{f+g x}}-\frac{(2 (e f-d g)) \operatorname{Subst}\left (\int \frac{1}{1-\frac{g x^2}{e}} \, dx,x,\frac{\sqrt{d+e x}}{\sqrt{f+g x}}\right )}{c f^2+a g^2}-\frac{\left (e \left (c d f+a e g-\sqrt{-a} \sqrt{c} (e f-d g)\right )\right ) \int \frac{1}{\sqrt{d+e x} \sqrt{f+g x}} \, dx}{2 \sqrt{-a} \sqrt{c} \left (c f^2+a g^2\right )}-\frac{\left (\left (d-\frac{\sqrt{-a} e}{\sqrt{c}}\right ) \left (c d f+a e g-\sqrt{-a} \sqrt{c} (e f-d g)\right )\right ) \int \frac{1}{\left (\sqrt{-a}+\sqrt{c} x\right ) \sqrt{d+e x} \sqrt{f+g x}} \, dx}{2 \sqrt{-a} \left (c f^2+a g^2\right )}+\frac{\left (e \left (c d f+a e g+\sqrt{-a} \sqrt{c} (e f-d g)\right )\right ) \int \frac{1}{\sqrt{d+e x} \sqrt{f+g x}} \, dx}{2 \sqrt{-a} \sqrt{c} \left (c f^2+a g^2\right )}-\frac{\left (\left (d+\frac{\sqrt{-a} e}{\sqrt{c}}\right ) \left (c d f+a e g+\sqrt{-a} \sqrt{c} (e f-d g)\right )\right ) \int \frac{1}{\left (\sqrt{-a}-\sqrt{c} x\right ) \sqrt{d+e x} \sqrt{f+g x}} \, dx}{2 \sqrt{-a} \left (c f^2+a g^2\right )}\\ &=\frac{2 (e f-d g) \sqrt{d+e x}}{\left (c f^2+a g^2\right ) \sqrt{f+g x}}-\frac{2 \sqrt{e} (e f-d g) \tanh ^{-1}\left (\frac{\sqrt{g} \sqrt{d+e x}}{\sqrt{e} \sqrt{f+g x}}\right )}{\sqrt{g} \left (c f^2+a g^2\right )}-\frac{\left (c d f+a e g-\sqrt{-a} \sqrt{c} (e f-d g)\right ) \operatorname{Subst}\left (\int \frac{1}{\sqrt{f-\frac{d g}{e}+\frac{g x^2}{e}}} \, dx,x,\sqrt{d+e x}\right )}{\sqrt{-a} \sqrt{c} \left (c f^2+a g^2\right )}-\frac{\left (\left (d-\frac{\sqrt{-a} e}{\sqrt{c}}\right ) \left (c d f+a e g-\sqrt{-a} \sqrt{c} (e f-d g)\right )\right ) \operatorname{Subst}\left (\int \frac{1}{-\sqrt{c} d+\sqrt{-a} e-\left (-\sqrt{c} f+\sqrt{-a} g\right ) x^2} \, dx,x,\frac{\sqrt{d+e x}}{\sqrt{f+g x}}\right )}{\sqrt{-a} \left (c f^2+a g^2\right )}+\frac{\left (c d f+a e g+\sqrt{-a} \sqrt{c} (e f-d g)\right ) \operatorname{Subst}\left (\int \frac{1}{\sqrt{f-\frac{d g}{e}+\frac{g x^2}{e}}} \, dx,x,\sqrt{d+e x}\right )}{\sqrt{-a} \sqrt{c} \left (c f^2+a g^2\right )}-\frac{\left (\left (d+\frac{\sqrt{-a} e}{\sqrt{c}}\right ) \left (c d f+a e g+\sqrt{-a} \sqrt{c} (e f-d g)\right )\right ) \operatorname{Subst}\left (\int \frac{1}{\sqrt{c} d+\sqrt{-a} e-\left (\sqrt{c} f+\sqrt{-a} g\right ) x^2} \, dx,x,\frac{\sqrt{d+e x}}{\sqrt{f+g x}}\right )}{\sqrt{-a} \left (c f^2+a g^2\right )}\\ &=\frac{2 (e f-d g) \sqrt{d+e x}}{\left (c f^2+a g^2\right ) \sqrt{f+g x}}-\frac{2 \sqrt{e} (e f-d g) \tanh ^{-1}\left (\frac{\sqrt{g} \sqrt{d+e x}}{\sqrt{e} \sqrt{f+g x}}\right )}{\sqrt{g} \left (c f^2+a g^2\right )}+\frac{\sqrt{\sqrt{c} d-\sqrt{-a} e} \left (c d f+a e g-\sqrt{-a} \sqrt{c} (e f-d g)\right ) \tanh ^{-1}\left (\frac{\sqrt{\sqrt{c} f-\sqrt{-a} g} \sqrt{d+e x}}{\sqrt{\sqrt{c} d-\sqrt{-a} e} \sqrt{f+g x}}\right )}{\sqrt{-a} \sqrt{c} \sqrt{\sqrt{c} f-\sqrt{-a} g} \left (c f^2+a g^2\right )}-\frac{\sqrt{\sqrt{c} d+\sqrt{-a} e} \left (c d f+a e g+\sqrt{-a} \sqrt{c} (e f-d g)\right ) \tanh ^{-1}\left (\frac{\sqrt{\sqrt{c} f+\sqrt{-a} g} \sqrt{d+e x}}{\sqrt{\sqrt{c} d+\sqrt{-a} e} \sqrt{f+g x}}\right )}{\sqrt{-a} \sqrt{c} \sqrt{\sqrt{c} f+\sqrt{-a} g} \left (c f^2+a g^2\right )}-\frac{\left (c d f+a e g-\sqrt{-a} \sqrt{c} (e f-d g)\right ) \operatorname{Subst}\left (\int \frac{1}{1-\frac{g x^2}{e}} \, dx,x,\frac{\sqrt{d+e x}}{\sqrt{f+g x}}\right )}{\sqrt{-a} \sqrt{c} \left (c f^2+a g^2\right )}+\frac{\left (c d f+a e g+\sqrt{-a} \sqrt{c} (e f-d g)\right ) \operatorname{Subst}\left (\int \frac{1}{1-\frac{g x^2}{e}} \, dx,x,\frac{\sqrt{d+e x}}{\sqrt{f+g x}}\right )}{\sqrt{-a} \sqrt{c} \left (c f^2+a g^2\right )}\\ &=\frac{2 (e f-d g) \sqrt{d+e x}}{\left (c f^2+a g^2\right ) \sqrt{f+g x}}-\frac{2 \sqrt{e} (e f-d g) \tanh ^{-1}\left (\frac{\sqrt{g} \sqrt{d+e x}}{\sqrt{e} \sqrt{f+g x}}\right )}{\sqrt{g} \left (c f^2+a g^2\right )}-\frac{\sqrt{e} \left (c d f+a e g-\sqrt{-a} \sqrt{c} (e f-d g)\right ) \tanh ^{-1}\left (\frac{\sqrt{g} \sqrt{d+e x}}{\sqrt{e} \sqrt{f+g x}}\right )}{\sqrt{-a} \sqrt{c} \sqrt{g} \left (c f^2+a g^2\right )}+\frac{\sqrt{e} \left (c d f+a e g+\sqrt{-a} \sqrt{c} (e f-d g)\right ) \tanh ^{-1}\left (\frac{\sqrt{g} \sqrt{d+e x}}{\sqrt{e} \sqrt{f+g x}}\right )}{\sqrt{-a} \sqrt{c} \sqrt{g} \left (c f^2+a g^2\right )}+\frac{\sqrt{\sqrt{c} d-\sqrt{-a} e} \left (c d f+a e g-\sqrt{-a} \sqrt{c} (e f-d g)\right ) \tanh ^{-1}\left (\frac{\sqrt{\sqrt{c} f-\sqrt{-a} g} \sqrt{d+e x}}{\sqrt{\sqrt{c} d-\sqrt{-a} e} \sqrt{f+g x}}\right )}{\sqrt{-a} \sqrt{c} \sqrt{\sqrt{c} f-\sqrt{-a} g} \left (c f^2+a g^2\right )}-\frac{\sqrt{\sqrt{c} d+\sqrt{-a} e} \left (c d f+a e g+\sqrt{-a} \sqrt{c} (e f-d g)\right ) \tanh ^{-1}\left (\frac{\sqrt{\sqrt{c} f+\sqrt{-a} g} \sqrt{d+e x}}{\sqrt{\sqrt{c} d+\sqrt{-a} e} \sqrt{f+g x}}\right )}{\sqrt{-a} \sqrt{c} \sqrt{\sqrt{c} f+\sqrt{-a} g} \left (c f^2+a g^2\right )}\\ \end{align*}
Mathematica [A] time = 0.891688, size = 340, normalized size = 0.54 \[ -\left (\frac{a d}{(-a)^{3/2}}-\frac{e}{\sqrt{c}}\right ) \left (\frac{\sqrt{d+e x}}{\sqrt{f+g x} \left (\sqrt{-a} g+\sqrt{c} f\right )}+\frac{\sqrt{\sqrt{-a} e+\sqrt{c} d} \tan ^{-1}\left (\frac{\sqrt{d+e x} \sqrt{-\sqrt{-a} g-\sqrt{c} f}}{\sqrt{f+g x} \sqrt{\sqrt{-a} e+\sqrt{c} d}}\right )}{\left (-\sqrt{-a} g-\sqrt{c} f\right )^{3/2}}\right )-\left (\frac{d}{\sqrt{-a}}-\frac{e}{\sqrt{c}}\right ) \left (\frac{\sqrt{d+e x}}{\sqrt{f+g x} \left (\sqrt{c} f-\sqrt{-a} g\right )}-\frac{\sqrt{\sqrt{-a} e-\sqrt{c} d} \tan ^{-1}\left (\frac{\sqrt{d+e x} \sqrt{\sqrt{c} f-\sqrt{-a} g}}{\sqrt{f+g x} \sqrt{\sqrt{-a} e-\sqrt{c} d}}\right )}{\left (\sqrt{c} f-\sqrt{-a} g\right )^{3/2}}\right ) \]
Antiderivative was successfully verified.
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Maple [B] time = 0.508, size = 8264, normalized size = 13.2 \begin{align*} \text{output too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (e x + d\right )}^{\frac{3}{2}}}{{\left (c x^{2} + a\right )}{\left (g x + f\right )}^{\frac{3}{2}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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